1. The problem statement, all variables and given/known data A diver running 2.2 m/s dives out horizontally from the edge of a vertical cliff and 2.5 s later reaches the water below. How high was the cliff? 2. Relevant equations Y=Yo+Vyo*t-.5gt^2 I have Y as being 0 (the point when they hit the water) and velocity of y at time zero being 2.2 m/s. 3. The attempt at a solution I used the equation above and substituted and got 0=y+(2.2)(2.5)-.5(9.8)(2.5^2) and got 25 for y, but my online homework says it's wrong. I've double checked and can't figure out where I went wrong.