- #1

- 36

- 0

My attempt: q^2 is divisible by 3, so q is divisible by 3. I can't prove that p is divisible by 3.

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter lordy12
- Start date

- #1

- 36

- 0

My attempt: q^2 is divisible by 3, so q is divisible by 3. I can't prove that p is divisible by 3.

- #2

- 1,425

- 1

Any integer that is not a perfect square has an irrational square root. What can you do with that?

- #3

JasonRox

Homework Helper

Gold Member

- 2,314

- 3

Any integer that is not a perfect square has an irrational square root. What can you do with that?

Personally, I have no idea what you can do with that.

- #4

JasonRox

Homework Helper

Gold Member

- 2,314

- 3

My attempt: q^2 is divisible by 3, so q is divisible by 3. I can't prove that p is divisible by 3.

Now, just re-write it as p^2 = q^2/3. What does that tell you about p?

Remember, p is an integer so p^2 is also an integer. And q is divisible by 3, but there is only one 3.

Finish it off from there.

- #5

- 1,425

- 1

A power has the same prime factors than its root.

- #6

- 682

- 1

3|q, rewrite q=3q'

- #7

- 36

- 0

oops...I completely disregarded the fact that p and q are integers.

sorry

sorry

Share: