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Divisibility proof using gcd

  1. Mar 7, 2012 #1
    Figured it out nvm
    Last edited: Mar 7, 2012
  2. jcsd
  3. Mar 7, 2012 #2


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    Are we to assume that (a,c) is the "greatest common denominator" of a and c?
  4. Mar 7, 2012 #3
    yes (a,b) is the GCD of a and b
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