- #1
audiowize
- 7
- 0
Hello,
If we are given that b3|a2, how do we show that b|a?
I started off looking at prime factorizations, but I could use a push in a more substantial direction.
If we are given that b3|a2, how do we show that b|a?
I started off looking at prime factorizations, but I could use a push in a more substantial direction.