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Do I have enough information to solve this?

  • #1
How would I solve this?

2 police officers are standing on a road. A motorist comes at 108km/hr(30m/s) The police take 2 s to assess the situation. Then their patrol car accelerates at 2.5m/s^2 for 15s after the 2s and then continues at uniform speed. How far from the observation point does the intersection take place? Assume the motorist maintains a constant speed of 108km/hr?
 

Answers and Replies

  • #2
25
0
Yes you do, assuming the question means the police react as the bike passes parallel to them.

using:

S = ut + 1/2*a*t2

You find that the police travel 281.25m in the 15 seconds they accelerate, plus the 2 seconds they waited, so in 17s they have traveled 281.25m and accelerated to a constant velocity of 37.5m/s

In this time the motorbike has traveled 17*30 = 510m so the police after 17s are a distance of 228.75m behind the bike

The relative speed between the two is 7.5m/s

So how long does it take to make up 228.75m at 7.5 m/s?

228.75 / 7.5 = 30.5s

plus the original 17s

30.5 + 17 = 47.5s until the police are level with the biker.
 
  • #3
Thank you ,but I still am not sure of the answer to "how far from the observation point did the intersection take place?"
 

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