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Does -e^(-infinity) equals 0?

  1. Oct 22, 2005 #1
    does -e^(-infinity) equals 0?
     
  2. jcsd
  3. Oct 22, 2005 #2
    The limit of e^x as x-->-infinity is 0.
     
  4. Oct 22, 2005 #3
    Are you referring to [itex]\lim_{x\rightarrow\infty} -e^{-x}[/itex] ?
     
  5. Oct 22, 2005 #4
    yes.......
     
  6. Oct 22, 2005 #5

    HallsofIvy

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    As kamataat said, [itex]\lim_{x\rightarrow\infty} e^{-x}= 0[/itex] and so
    [itex]\lim_{x\rightarrow\infty} -e^{-x}= -0= 0[/itex].
     
  7. Oct 22, 2005 #6
    i see. thanks.
     
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