# Does L'Hospital's rule apply to complex functions?

Homework Helper
Gold Member
I have to evaluate

$$\lim_{x\rightarrow \infty} \frac{x-1}{e^{ipx/\hbar}}$$

is this equal to

$$\lim_{x\rightarrow \infty} \frac{\hbar}{ip e^{ipx/\hbar}}$$

??

Gold Member
L'Hospital's rule only applies when a limit approaches $\frac{0}{0}$ or $\frac{\infty}{\infty}$. Niether is the case here because $\lim_{x\rightarrow\infty}e^{ix}$ does not exist. The real and imaginary parts oscilate between -1 and 1 as x approaches infinity. Your limit is equal to:
$$\lim_{x\rightarrow \infty} \frac{x-1}{e^{ipx/\hbar}} =\lim_{x\rightarrow \infty} (x-1)\cos{\frac{ipx}{\hbar}}-i(x-1)\sin{\frac{ipx}{\hbar}$$
So the real and imaginary parts both oscillate between larger and larger positive and negative numbers as x gets larger, so the limit does not exist.