# Does limit exist? (i have test tomorrow morning!)

## Homework Statement

Does the limit of (2y*x^2)/(4x^2-3y) exist as (x,y) -> (1,1)? If so what is the limit?

## The Attempt at a Solution

So at first I thought I could just plug (1,1) into the equation and get two. My study buddy said that you have to make sure it approaches the same thing from every direction else the limit DNE. If it approaches the limit from x=0 then it equals zero, and same with y. but if you take the limit with y=x then it comes out to two.

Are we overthinking this? Can't you just plug it in and ignore the "approaching from x=0" since x can't approach from zero because it goes to 1?

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jbunniii
Homework Helper
Gold Member
Hang on, I had typos in my previous post. Will resubmit with corrections.

jbunniii
Homework Helper
Gold Member
Your buddy is right that if you find different limits when approaching via different paths, then the limit does not exist.

If you put $y = x^2$ (I assume you meant this, not $y=x$), then you get $2x^4/x^2 = 2x^2$, which indeed approaches $2$ as $x \rightarrow 1$.

However, "approaching via $x=0$" makes no sense in this problem because then you won't approach the point $(1,1)$.

jbunniii
Homework Helper
Gold Member
Here's another approach to the problem. Note that there is no problem with the denominator as you approach $(1,1)$. So the quotient is well defined in the vicinity of that point. The numerator and denominator are continuous functions of $x$ and $y$ (proof?), so the quotient is also continuous in a neighborhood of $(1,1)$. What can you conclude?

HallsofIvy
Homework Helper
Tell your study budy he is "overthinking" this. The only time there is a "problem" with a limit so that you need to check "along different paths" is if taking numerator and denominator separately go to 0 so that you get the "indeterminate form" 0/0. Here, that does not happen. In consequence, "the quotient is continuous in a neighorhood of (1, 1)" as jbunniii says.

Borek
Mentor
Somehow I miss mentioning of one-side limits. I mean - you can have a one side limit(s) in the point, but no limit. Am I right?

jbunniii