# Does the converse of Lenz's Law act to compensate for E flux?

1. Oct 4, 2011

Lenz's Law says that the induced emf from a change in B flux creates a B field that compensates for the flux change. I know that a changing E field induces a magnetic field as well, but does that magnetic field act in a way to compensate for the change in the E field? Or is that not physically possible? If it does do that, then why is there no minus sign in Maxwell's law of induction

$\oint$B$\cdot$ds=$\mu$$_{0}$$\epsilon$$_{0}$$\frac{d\Phi_{E}}{dt}$

$\oint$E$\cdot$ds=-$\frac{d\Phi_{B}}{dt}$