# Does the Corioulis force effect our blood cycle?

Does the Corioulis force effect our blood cycle[?]

nbo10
It would but I doubt you would ever be able to measure it.

JMD

Not noticeably... you don't see significant effect from the Coriolis force except at very large scales, like with artillery shells. The maximum acceleration from Coriolis effects on the Earth is ~velocity/10,000 m/s^2, if that gives you an idea.

Does the Coriolis force, in any way, pertain to the centrifugal force of the earth? Should "Coriolis" even be capitalized? If so, why?

Zefram
It's capitalized because it was the guy's last name.

Mulder
Originally posted by MajinVegeta
Does the Coriolis force, in any way, pertain to the centrifugal force of the earth?

You get a Coriolis acceleration in addition to Centrifugal for example on a plane flying round the Earth - that is when you have something moving inside a rotating frame. For the 'person on the equator' example, only a centrifugal acceleration is acting because he's standing still. If that's what you're asking? Happy to try to explain better/further if you want...

Staff Emeritus
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The Coriolis force tends to turn a vector clockwise in the Northern hemisphere and counterclockwise in the Southern hemisphere, with a force proportional to the sine of the latitude. So it is zero at the equator, where latitude is 0o, because sine 0o = 0. And it is maximum at the poles, where latitude is 90o mbecause the sine function has its maximum there, where sine 90o = 1. At the poles the rate is (duh) 360o per 24 hours or 15o per hour.

Originally posted by Mulder
You get a Coriolis acceleration in addition to Centrifugal for example on a plane flying round the Earth - that is when you have something moving inside a rotating frame. For the 'person on the equator' example, only a centrifugal acceleration is acting because he's standing still. If that's what you're asking? Happy to try to explain better/further if you want...

The plane you described, how exactly is it effected by the Coriolis force? (I know it's experiencing free fall)

Mulder
Some of http://www.nottingham.ac.uk/physics/ugrad/courses/mod_home/f31am1/coriolis.htm [Broken] you may understand.

The Coriolis force acts at a right angle to the plane's velocity and the Earth's angular velocity. The right hand rule can be used to work out exactly which direction the force will be in - it depends on the direction of the plane. Just as an example, if a plane was in the Northern hemisphere, flying North, then the Coriolis force would act on the plane in a Easterly(!oops) direction (aswell as Centrifugal acting away from the surface of the Earth). You will probably need some understanding of the basics of vectors to fully know why, but just check out the link and then come back and ask more if you want

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Is the "w" always defined as the wave front? I read in my book, "relativity beyond eintsien", that it is defined as the wave front relative to a Newtonian co-ordinate system, K0.

Mulder
The 'w' here in '-2mw x v' is the angular velocity of the Earth ie the Earths velocity / Earth radius, a constant 7.27e-05 radians per second. Forget relativity, this is good ole' Mechanics

NEOclassic
Centrifugal force vis-a-vis Coreolis force!

Originally posted by MajinVegeta
Does the Coriolis force, in any way, pertain to the centrifugal force of the earth? Should "Coriolis" even be capitalized? If so, why?

Hi MV,

In Feynman notes Vol I Chapter 19 Richard points out that Centrifugal force is radial while Coriolis Force is tangential. In Chap 20 of Vol I he gets real when he reminds us that because angular momentum is a dipolar phenomenon, interaction with other dipoles demands vector cross-product, which gives perpendicular torque when the loop is inertial and perpendicular dipolar magnetism when the loop is electrostatic.
Most every High School Physics Lab has a bicycle wheel with a handle on each side of its axle. When you spin it and try to turn it, it tugs noticably to bend sidways toward the floor. Cheers, jim

In Feynman notes Vol I Chapter 19 Richard points out that Centrifugal force is radial while Coriolis Force is tangential.

What does it mean by "Coriolis force is tangential"? My definition of tangent is a dent.

In Chap 20 of Vol I he gets real when he reminds us that because angular momentum is a dipolar phenomenon, interaction with other dipoles demands vector cross-product, which gives perpendicular torque when the loop is inertial and perpendicular dipolar magnetism when the loop is electrostatic.

First off, I have zero knowledge of dipoles. I don't know anything about biophysics.

Originally posted by Mulder
The 'w' here in '-2mw x v' is the angular velocity of the Earth ie the Earths velocity / Earth radius, a constant 7.27e-05 radians per second. Forget relativity, this is good ole' Mechanics

How do you know when relativity is involved and when it isn't?

Also, isn't K0 Newtonian mechanics?

-2mw x v

so the -2 is multiplied by the mass, and then velocity/earth's radius? and then x, position and velocity are sort of left out, so what does that indicate?

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A radian is a measurement of angle.

One radian is the distance around the circumference which is equal to the radius of the circle.

So if you have a circle of radius 2, start at one point on the circumference, and start walking, you will have traveled an angle of one radian when you have walked a distance of 2.

In the grand scheme of things, relativity is always involved. For most human sized problems (which means speeds up to the order of 10000s of km/hour, distances on the orders 10,000s of km), relativity can be completely ignored because it has such a tiny effect.

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So if you have a circle of radius 2, start at one point on the circumference, and start walking, you will have traveled an angle of one radian when you have walked a distance of 2.

so the radius=radian?? Hmm...not from what I remember. So I must have misunderstood. Can you give me the formula? (it'd give me a better idea)

NEOclassic

Originally posted by MajinVegeta
so the radius=radian?? Hmm...not from what I remember. So I must have misunderstood. Can you give me the formula? (it'd give me a better idea)

Hi again MV,
the radius of the circle is a "length", the arc of curved length subtending the angle identified as a radian has a length equal to one radius long. There are 2 x 3.14159-- radian angles in a full circle, and there are 2 x 3.14159- radius lengths in the circumference of the circle.
Cheers, Jim

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Sorry, I must not have been too clear.

Cut out a 1 radian piece of a circle. Take the remaining piece of the circumference. If you stretch that arc out so it's straight, it will be the same length as the radius is.

But there is a formula! Isn't it circumference/radius?

Staff Emeritus