- #1

frankR

- 91

- 0

I used this theorem: N N

^{-1}= I

_{n}

Thus:

[i,1;-1,i]*[a,b:c,d]=[1,1;1,1]

I then found:

ia+c=1

ib+d=1

-a+ic=1

-b+id=1

Can I conclude an inverse does not exist. If so, how?

If not, what do I do?

Thanks,

Frank

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- Thread starter frankR
- Start date

- #1

frankR

- 91

- 0

I used this theorem: N N

Thus:

[i,1;-1,i]*[a,b:c,d]=[1,1;1,1]

I then found:

ia+c=1

ib+d=1

-a+ic=1

-b+id=1

Can I conclude an inverse does not exist. If so, how?

If not, what do I do?

Thanks,

Frank

- #2

Hurkyl

Staff Emeritus

Science Advisor

Gold Member

- 14,967

- 19

What theorems have you learned about invertible matrices? (e.g. have you learned anything about how to tell if a matrix is invertible based on its determinant)

Or, you could apply the algorithm for computing inverses and see if you get an answer or if its impossible.

- #3

frankR

- 91

- 0

Originally posted by Hurkyl

Or, you could apply the algorithm for computing inverses and see if you get an answer or if its impossible.

I just found this:

N

det(NN

I'm a little rusty on my linear algebra, plus I got a concusion yesterday.

- #4

arcnets

- 508

- 0

Hurkyl has told you what I

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