Cannonball fired on 45 deg angle from horizontal. Initial position is origin. initial velocity 100sqrt(2) ft/sec. Trajectory is y=x-(x/25)^2 where y>=0.(adsbygoogle = window.adsbygoogle || []).push({});

How far till it hits the ground? 312.5

What's the max height? 156.25

Here is what I got m(a) = 2*-(1/625)a + 1 = 0 which = -(1/312)a + 312 = 0

-(1/625)*312.5^2+312.5 = 156.25

Do you agree????

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Does this look right? Cannonball question

Loading...

**Physics Forums | Science Articles, Homework Help, Discussion**