- #1
mathatesme
- 4
- 0
Cannonball fired on 45 deg angle from horizontal. Initial position is origin. initial velocity 100sqrt(2) ft/sec. Trajectory is y=x-(x/25)^2 where y>=0.
How far till it hits the ground? 312.5
What's the max height? 156.25
Here is what I got m(a) = 2*-(1/625)a + 1 = 0 which = -(1/312)a + 312 = 0
-(1/625)*312.5^2+312.5 = 156.25
Do you agree?
How far till it hits the ground? 312.5
What's the max height? 156.25
Here is what I got m(a) = 2*-(1/625)a + 1 = 0 which = -(1/312)a + 312 = 0
-(1/625)*312.5^2+312.5 = 156.25
Do you agree?