in int[6/(x^2+3)^2] i use 3tanU=x, dx=3sec(u)^2 du(adsbygoogle = window.adsbygoogle || []).push({});

using that i get to .... int[1+cos2u]= u + sin2u/2 = u +sin u cos u... but subing back in with trig doesnt give me the right answer... any help with this method?

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# Does this make sense

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