- #1

- 81

- 0

using that i get to .... int[1+cos2u]= u + sin2u/2 = u +sin u cos u... but subing back in with trig doesnt give me the right answer... any help with this method?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter badtwistoffate
- Start date

- #1

- 81

- 0

using that i get to .... int[1+cos2u]= u + sin2u/2 = u +sin u cos u... but subing back in with trig doesnt give me the right answer... any help with this method?

- #2

- 584

- 0

Instead of setting x = 3tan(u) try...

[tex]

x = \sqrt 3 \tan \theta \Rightarrow dx = \sqrt 3 \sec ^2 \theta d\theta

[/tex]

- #3

- 81

- 0

- #4

- 584

- 0

Share: