A cargo plane is dropping supplies to a group of people dogsledding acoss Antarctica. The plance drops the package when it is directly above the group of people at an altitude of 1950m. The dogsled travels at 5.68m/s and reaches the supplies in 6.70mins. What was the speed of the cargo plane?(adsbygoogle = window.adsbygoogle || []).push({});

well I`m assuming that the plane and dogsled are traveling in opposite directions. So lets make the dogsled travel in the (+)ve direction and the plane traveling in the (-)ve direction.

Xo = o

X = ??

to = 0s

t = 402s

Vdogsled = 5.68m/s

Vplane = ???

and then I used this equation: X = Xo + Vot to determine X

X = 0 + 5.68m/s(402s)

X = 2283.36m

then using tan^-1 (theta) I found the angle which is 40.50degrees

but now I'm stuck not quite sure what to do next - not quite sure if I'm on the right tracl :uhh:

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# Homework Help: Dog Sledding

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