1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Dogs pulling a sled

  1. Sep 27, 2013 #1
    1. The problem statement, all variables and given/known data
    The sled dog in figure drags sleds A and B across the snow. The coefficient of friction between the sleds and the snow is 0.10.

    If the tension in rope 1 is 150 N, what is the tension in rope 2?

    [Sled A, 100kg]---1----[Sled B, 80kg]--2--Dog pulling


    This problem was solved here, but I want to know why I come up with different results. I see in the link that they did not account for the friction. Since mu is given, we should use friction, right? Why did they ignore it there and come up with the answer?


    2. Relevant equations

    Net force and a = F/m

    3. The attempt at a solution

    First I made axis for A, with normal A pointing up at 980N, F_G_a pointing down at -980, f_k_a (friction) pointing left, away from the dig, at -(.10)(980) = -98N. Tension on the rope to the right was 150 N. Sum, F_net_x_a = (150)-(98)=52 => a = 0.52 m/s^2

    But that's not the acceleration given in the link. Like I said, they ignored friction, I did not. Why is ignoring friction resulting in the right answer?

    [I won't continue to work the problem here because it will be wrong until I figure out the right acceleration.]

    Thanks
     
  2. jcsd
  3. Sep 27, 2013 #2
    Note: I correctly solved it using friction. But in the link, they got the same answer without friction...
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Dogs pulling a sled
  1. Dog Sledding (Replies: 4)

  2. Sled Dogs work? (Replies: 2)

  3. Dog sled (Replies: 2)

Loading...