define the natural domain and range for f(x,y) = 1/sqrt(x^2-y)(adsbygoogle = window.adsbygoogle || []).push({});

I get D= {(x,y)|x^2-y>0} same as saying y can not equal x^2

R= {(x,Y)|f>0}

can someone tell me if ive approached this correctly?

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# Homework Help: Domain and range f(x,y)

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