1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Domain Issues

  1. Sep 21, 2008 #1
    1. The problem statement, all variables and given/known data

    Find a. (f+g)(x) b. (f-g)(x) c. (fg)(x) d. (f/g)(x)

    f(x)=2x-5 & g(x)=4

    2. Relevant equations

    (f+g)(x)=2x-1
    (f-g)(x)=2x-9
    (fg)(x)=8x-20
    (f/g)(x)=2x-5/4

    3. The attempt at a solution
    When I've completed all the other equations, I'm stuck on domain. I'm thinking that its all reals, but I'm not quite sure on how this is true. Is it because it cannot equal zero, or a non-negative number?

    In other other words how exactly do you find the domain?
     
    Last edited: Sep 21, 2008
  2. jcsd
  3. Sep 21, 2008 #2
    Just a little note, they are actually asking for the *largest* possible domain of each function over the reals, as you can give a function any domain you want, as long as the function is defined for every element of its domain.
    Is there any value of x for which any of your functions does not yield a real number? If they exist, these x's cannot be in any domain of your function.
    Hint: The identity function I(x) = x is defined for all real numbers x. Your functions are just real numbers added to real multiples of this function. Ie., it boils down to showing that if x is a real number, then kx is also a real number for real k.
    PS. Your (f/g)(x) is missing the division by 4.
     
  4. Sep 21, 2008 #3
    fg, f+g and f-g are defined everywhere, where f and g are both defined. f/g is defined everywhere, where f and g are both defined and g does not equal zero.
     
  5. Sep 21, 2008 #4
    What does the k represent? So if x is a real number then the domain should include all reals? So basically to find the domain you should plug in some x's to see if they aren't real numbers?

    I fixed the (f/g) forgot to add the /4.

    What!?
     
  6. Sep 21, 2008 #5

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Yes, xnoname0206 is correct. If the domains of f and g are not the same, the domains of fg, f+ g and f-g are the intersections of the domains of f and g. That is what xnoname0206 meant by "where f and g are both defined". f/g is defined on the intersection of the domains minus points where g(x)= 0.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Domain Issues
  1. Domain and Range (Replies: 4)

  2. Domain of a function (Replies: 4)

  3. Domain of a function (Replies: 5)

  4. Domain of the function (Replies: 2)

  5. Finding domain (Replies: 6)

Loading...