- #1

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f(x) = (2x^2 + 25)^(0.5) + 1

as we can see that , f(x) will always be greater or equal to zero , was wondering what would the domain be ? Could anyone help me out ? thanks

- Thread starter garyljc
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- #1

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f(x) = (2x^2 + 25)^(0.5) + 1

as we can see that , f(x) will always be greater or equal to zero , was wondering what would the domain be ? Could anyone help me out ? thanks

- #2

nicksauce

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- #3

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what about Z that denotes integers

is that a possible answer ?

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Maybe I can explain what the domain is for you. Think of the function like a machine. The domain is all of the possible inputs that you put in and the range is all of the possible answers that come out. Pretty simple.

So, can x's be something other than integers(1,2,3...)? what about .23614? Do you still get a valid answer? If so, (you do lol) then the integers are not all of the possible inputs. Hopefully that will help.

- #5

Gib Z

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That is because really, the domain is not meant to be "found", it is already part of the original functions definition. The function f(x) = x, 0 < x < 1, is a very different function to g(x)= x, 0< x < infinity.

- #6

HallsofIvy

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The fact that the function value "will always be greater or equal to zero" has nothing to do with the domain- it's the fact that the function value always

f(x) = (2x^2 + 25)^(0.5) + 1

as we can see that , f(x) will always be greater or equal to zero , was wondering what would the domain be ? Could anyone help me out ? thanks

A possible answer to what question? Since the integers are a subset of all real numbers, certainly this function is defined for all integers. But the function "[itex]f(x)= \sqrt{2x^2+ 25}+ 1[/itex] with domain all integers" is a very

what about Z that denotes integers

is that a possible answer ?

- #7

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Typically it's denoted D(f)I was wondering if there's any symbol i could use for the domain of this question \

- #8

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thanks all for your help ... much appreciated ... now i understand more clearly thanks =)

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