1. The problem statement, all variables and given/known data A rectangle has one vertex in quadrant I at the point (x,y) which lies on the graph of y = 2x^2 and another vertex at the point (-x, y) in the second quadrant and the other vertices on the x axis at (-x, 0) and (x, 0) What is the domain of the area function? y = 2x^2 = w l = 2x Vertices: (-x, 0) (x,0) (-x,y) (x,y) 2. Relevant equations 2x(2x^2) = 4x^3 2x = 2x^2 3. The attempt at a solution Find the zeros: 0 Find the maximum area: 1 [0,1] is the domain But I am not so sure about this. On the one hand a rectangle can't have infinite area. On the other hand, 4x^3, the area function goes all the way to infinity. So am I approaching this wrong? How do I find the maximum area if the function has no max? I know that x cannot be any lower than 0 since that would mean negative area and negative area only applies in integral calculus.