If [tex] f(x,y) = e^{-x-2y} [/tex] find [tex] P(X<Y) [/tex].(adsbygoogle = window.adsbygoogle || []).push({});

So is this equaled to [tex] 1 - P(X>Y) = 1 - \int\limits_{0}^{\infty} \int\limits_{0}^{x} e^{-x-2y} \ dy \ dx = \frac{1}{3}?[/tex]

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# Homework Help: Domain probability problem

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