1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Don't know how to start

  1. Nov 30, 2004 #1
    Here is my question I'm not sure even how to come up with the answer:

    A circular pizza of radius R has a circular piece of radious R/2 removed from one side. The center of gravity has moved from C to C' along the x axos. Show that the distance from C to C' is R/6. Assume the thickness and density of the pizza are uniform throughout.

    If anyone could give me some pointers they would be greatly appreciated.
     
  2. jcsd
  3. Dec 1, 2004 #2
    Find the center of mass of the pizza (in the center, obviously) and then find the center of mass of the removed piece.

    Xcom = (m1x1 + m2X2) / (total mass)

    If the pizza has density d, then the total area must be R^2*pi - (R/2)^2*pi. This goes in the denominator. Now you simply find the center of mass of the removed piece, which should be (R/2)^2*pi. Multiply this by R/2 (the distance to the center). I hope that helps some.
     
  4. Dec 3, 2004 #3

    Doc Al

    User Avatar

    Staff: Mentor

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?