- #1

- 31

- 0

I can't figure out how the heckle you are supposed to solve for this without the distance. Is it me or the question, if it's me; how bout' some equations.

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- Thread starter Supaiku
- Start date

- #1

- 31

- 0

I can't figure out how the heckle you are supposed to solve for this without the distance. Is it me or the question, if it's me; how bout' some equations.

- #2

- 119

- 2

The time period is just

[tex] T = 2 \pi \sqrt{\frac{m}{k}}[/tex]

spacetime

www.geocities.com/physics_all/index.html

- #3

- 31

- 0

Thanks! but uh... where's that from? I can't figure it out :(

EDIT: nvm, Thanks again:D

EDIT: nvm, Thanks again:D

Last edited:

- #4

- 119

- 2

[tex]x=Asin\omega t[/tex]

where

[tex]\omega = \sqrt\frac{k}{m}

[/tex]

From this, the time period of motion is [tex]\frac{2\pi}{\omega}[/tex]

So, you can derive that formula.

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