Why Do Equations for Doppler Effect Differ for Moving Source and Observer?

In summary, the principle of Doppler effect states that the apparent frequency of a wave to a stationary observer is determined by the equation f' = true frequency * speed of wave / (speed of wave + speed of source). Similarly, the apparent frequency of a wave to a moving observer is given by f' = original frequency * (speed of wave - speed of observer) / speed of wave. However, these two equations yield slightly different values, despite the fact that the velocity of the source and observer are relative values. This is because the equations are based on different approaches - one considering the apparent wavelength and the other considering the apparent velocity of the wave. The difference in values is due to the medium through which the wave is traveling. In
  • #1
Terocamo
47
0
I have just read about the principle of Doppler effect.
However there is a point which seemed a bit tricky.
According to the book, when the source of wave is moving the apparent frequency to a stationary observer is given by the equation:
f'=true frequency*speed of wave/(speed of wave + speed of source)

On the other hand, if an observer is moving towards a stationary source, the frequency is given by:
f'=original frequency * (speed of wave - speed of observer)/(speed of wave)

But referring to the basic principle of displacement, the velocity of the observer and that of source is a relative value. So theoretically there is no difference whether is the source moving or the observer moving, because its only relative motion.
However, with respect to the equation, they are not exactly equal (very close though).

What I want to know is the reason behind this or is there something that I missed?
 
Physics news on Phys.org
  • #2
the speed at which the two are approaching each other is the same in both reference frames, therefor the equation is the same in both cases. no?
 
  • #3
In the first equation, if you consider the speed of the source to be a negative value it will work out just fine.
In the second equation, if you also consider the speed of the observer to be a negative value (which is then multiplied by -1) it too will also work out fine.
 
  • #4
Fact is the equation is not the same.
The apparent frequency of a moving source differs from the that of a moving observer. This is what I am puzzled by the two equation.

To be more detail, the two equation is based on two different approach.
For a moving source, the apparent wavelength is first considered. But for a moving observer, the apparent velocity of the traveling wave is first considered.
These give rise to two different equation as stated in the first post. This two equation give different values.
 
  • #5
billslugg said:
In the first equation, if you consider the speed of the source to be a negative value it will work out just fine.
In the second equation, if you also consider the speed of the observer to be a negative value (which is then multiplied by -1) it too will also work out fine.


My true confusion is not about the direction of the velocity vector. It is about the phenomenon that the two equation give two very close but not the identical (which I think should be) regardless that there is no difference whether the source is moving or the observer is moving.
 
  • #6
Terocamo said:
But referring to the basic principle of displacement, the velocity of the observer and that of source is a relative value. So theoretically there is no difference whether is the source moving or the observer moving, because its only relative motion.
That would be true if there was no medium, as is the case for light in a vacuum. But here the speed of the wave is with respect to the air (presumed stationary). The speed of the wave with respect to the observer depends on whether the observer moves with respect to the air.
 

1. What is the Doppler effect?

The Doppler effect is a phenomenon in which the observed frequency of a wave (such as sound or light) differs from the emitted frequency due to relative motion between the source of the wave and the observer.

2. How does the Doppler effect work?

The Doppler effect is based on the principle that when a wave source and an observer are moving towards each other, the observer will perceive a higher frequency of the wave, while if they are moving away from each other, the observer will perceive a lower frequency.

3. What causes confusion in understanding the Doppler effect?

Many people struggle to understand the Doppler effect because it involves relative motion and changes in frequency, which can be difficult to visualize. Other factors such as the speed of the wave source and the medium it is traveling through can also affect the perceived frequency and add to the confusion.

4. How is the Doppler effect used in real life?

The Doppler effect has many practical applications, such as in weather radar systems, medical ultrasound, and police radars. It is also used in astronomy to determine the speed and direction of celestial objects.

5. Can the Doppler effect be observed with all types of waves?

Yes, the Doppler effect can be observed with all types of waves, including sound waves, light waves, and even water waves. However, the effect may be more noticeable with waves that have a longer wavelength, such as sound waves, as the change in frequency is more significant.

Similar threads

  • Classical Physics
Replies
16
Views
1K
  • Classical Physics
2
Replies
64
Views
5K
  • Introductory Physics Homework Help
Replies
8
Views
188
  • Classical Physics
Replies
5
Views
1K
Replies
3
Views
701
  • Classical Physics
Replies
3
Views
475
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
3K
Replies
3
Views
430
  • Introductory Physics Homework Help
Replies
4
Views
2K
Back
Top