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Doppler shift of light

  1. Oct 5, 2006 #1
    I have to calculate the suns period time, when given the following information;

    "The H_{alpha} line has the wavelength [itex] \lambda_0 = 656.1~nm [/itex]. Measuring this spectrum from opposite sites of the suns equator, shows that there is a difference between that is [itex] \Delta \lambda=9\times 10^{-12}~m [/itex]. Asume that this effect is due to the rotation of the sun. Find the period, when the suns radius is 1.4 x 10^6 km."

    Wouldn't the difference just be (if calculated relativisticly)

    [tex] \Delta \lambda = \left( \sqrt{\frac{1+v/c}{1-v/c}} - \sqrt{\frac{1-v/c}{1+v/c}} \right)\lambda_0 [/tex]

    Then just solving for v in that equation, and the periode would then be [itex]2\pi r/v[/itex]? I just want to know if my assumption is correct, because I keep getting the wrong answer. If the assumption is correct then I just have better check my math.
  2. jcsd
  3. Oct 5, 2006 #2


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    Staff: Mentor

    Why do you need to calculate it relativistically? It's just a doppler frequency shift, not a gravitational red shift.
  4. Oct 5, 2006 #3
    Yea why wouldn't I just calculate it classical, alot less algebra, and gives the right answer. But even though calculating relativisticly I should get and answer almost equal to the classical one. But then again, I must have made an error in the calculation. Thanks any way.
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