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Dot placement

  1. Nov 4, 2005 #1
    one more electro-magnetic question:
    here's the set-up: two inductors, the A-B has a signal source hooked-up, C-D is open circuit.
    Code (Text):

    ->i1
    A       C
    )    (    +
    )    (    V2
    )    (    -
    B       D
     
    i1 is given as a triangular wave, v2 as a step wave for:
    0 < t < 0.5, i1 has negative slope below t-axis, v2=4;
    0.5<t<1, i1 has positive slope below t-axis, v2 = -4;
    1<t<1.5, i1 has positive slope above t-axis, v2 = 0

    so, i clearly see that voltage is derivative of current and there is a negative sign involved, so the dots are placed diagonally?
    If not, could you explain that as well?
    Thanks in advance...
     
  2. jcsd
  3. Nov 8, 2005 #2
    solved

    well... yeah, they should be on the opposite side, i think i got the idea....
     
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