Dot product of v and v'

  • #1

Main Question or Discussion Point

In a book I was reading, it says
F=mv'=P'

so dot producting on both sides with v

Fv = mv ⋅ dv/dt = 1/2 m d(v2)/dt = d(1/2 m v^2)/dt


I really don't get how v ⋅ dv/dt = 1/2 d(v2)/dt.
I have seen few threads and they say it's about product rule, but they don't really explain in detail.

Could anyone help me with this?
 

Answers and Replies

  • #2
PeroK
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In a book I was reading, it says
F=mv'=P'

so dot producting on both sides with v

Fv = mv ⋅ dv/dt = 1/2 m d(v2)/dt = d(1/2 m v^2)/dt


I really don't get how v ⋅ dv/dt = 1/2 d(v2)/dt.
I have seen few threads and they say it's about product rule, but they don't really explain in detail.

Could anyone help me with this?
Welcome to PF!

##v^2 = \textbf{v.v}##

Can you now differentiate that equation?
 
  • #3
11,280
4,741
V^2 = V . V

And the time derivative of it is V' . V + V . V'
 
  • #4
Welcome to PF!

##v^2 = \textbf{v.v}##

Can you now differentiate that equation?

V^2 = V . V

And the time derivative of it is V' . V + V . V'

Oh.. I see. I did not now that d(x ⋅ y)/dt = x' ⋅ y + x ⋅ y'

Knowing this, going right from left is easy, but I guess going left to right needs some practice to spot!

Thank you both peroK and Jedishrfu!
 
  • #5
19,677
3,987
In Cartesian component form, what is ##\vec{v}\centerdot d\vec{v}##?

Chet
 

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