# Dot product wagon incline

1. Jun 23, 2010

### nameVoid

A person pulls a wagon up an incline that makes an angled of 30 deg with the horizontal with a force on the handle of 30 pounds which makes an angel of 30 deg with the incline find the work done in pulling the wagon 100 ft
20cos30 will be a force along the surface of the incline and since vectors are in the same direction force*distance 20cos30*100=1000sqrt(3) which is the same as if you were to remove the incline?

2. Jun 23, 2010

### Staff: Mentor

Do you know about punctuation? Without punctuation it's much more difficult to parse what you have written.

The force applied is NOT in the same direction as the wagon is moving.

3. Jun 23, 2010

### nameVoid

20lbs 30 degrees

4. Jun 23, 2010

### Staff: Mentor

The pulling force is being applied at an angle (not angel) of 60 degrees to the horizontal.

5. Jun 23, 2010

### nameVoid

I would also suppose taking the force vector to be <10,10sqrt(3)>=a and the distance vector <50sqrt(3),50>=b
work= a*b =500sqrt(3)+500sqrt(3)=1000sqrt(3)
but taking the force vector along the incline to be 20cos30 and the distance 100 ft along the incline gives the same results

6. Jun 24, 2010

### Staff: Mentor

How did you get 20 cos(30 deg)?