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Double-angle formula

  1. Nov 30, 2011 #1
    I need to get from [tex]\cosh^2(v)-2\cos(u)\cosh(v) + 4\cos^2(\frac{u}{2})\sinh^2(\frac{v}{2}) + 1[/tex] to [tex](1+\cosh(v))(\cosh(v)-\cos(u))[/tex] using double angle formulae.
     
  2. jcsd
  3. Nov 30, 2011 #2
    Turn the double angle formulae into half-angle formulae, then it should be a piece of cake.
     
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