• Support PF! Buy your school textbooks, materials and every day products Here!

Double Atwood machine

  • Thread starter Calpalned
  • Start date
  • #1
297
6

Homework Statement


The double Atwood machine shown in the figure has frictionless, mass-less pulleys and cords.
Determine the acceleration of mA, mB, mC.
GIANCOLI.ch04.p56.jpg


Homework Equations


F = ma

The Attempt at a Solution



http://photo1.ask.fm/779/725/638/-259996976-1shhdoh-qms4ifsem3hthf/preview/IMG_4082.jpg [Broken]
http://photo1.ask.fm/905/398/673/-59997000-1shhdp1-2726aartaqghh2f/preview/IMG_4083.jpg [Broken]
http://photo1.ask.fm/916/959/786/-239996977-1shhdpk-78i75a0215n926k/preview/IMG_4084.jpg [Broken]
http://photo1.ask.fm/333/391/062/-249996981-1shhdrb-eeemt2tkfheqfp0/preview/IMG_4085.jpg [Broken]

What did I do wrong?
 
Last edited by a moderator:

Answers and Replies

  • #2
BvU
Science Advisor
Homework Helper
2019 Award
13,004
3,003
First I see aa = ab , later on it becomes aa = -ab ?
 
  • #3
ehild
Homework Helper
15,426
1,823
The accelerations of A and B are equal in magnitude with respect to the hanging pulley, which accelerates, too.
 
  • #4
BvU
Science Advisor
Homework Helper
2019 Award
13,004
3,003
Oops o:)
 
  • #5
297
6
Here is the answer given in my solutions manual.

Because the pulleys are massless, the net force on them must be 0. Because the cords are massless, the tension will be the same at both ends of the cords. Use the free-body diagrams to write Newton’s second law for each mass. We take the direction of acceleration to be positive in the direction of motion of the object. We assume that mC is falling, mB is falling relative to its pulley, and mA is rising relative to its pulley. Also note that if the acceleration of mA relative to the pulley above it is aR , then aA = aR + aC. Then, the acceleration of mB is aB = aR - aC since aC is in the opposite direction of aB .

Even though mA and mB are moving in opposite directions, how can they both be considered moving in the positive direction?

The acceleration of m_A relative to the free pulley should be the acceleration of the free pulley plus the acceleration of m_A. The free pulley is rising and mA is rising too. Therefore, aR = aC + aA. Why is it necessary to consider the free pulley in the first place? I don't see any problem with ignoring it (my original attempt doesn't seem to have an errors) but I somehow got the wrong answers.


Finally, what's the error in my original attempt in the starting post in this thread?
 
  • #6
Nathanael
Homework Helper
1,650
239
Even though mA and mB are moving in opposite directions, how can they both be considered moving in the positive direction?
ma and mb are not necessarily moving in opposite directions. It's only with respect to the lower pulley that they move in opposite directions. So in reality, they can both be moving in the same direction.

Finally, what's the error in my original attempt in the starting post in this thread?
Your error was the equation aa = -ab... This is not true! Imagine aa = ab ... They should both be at rest with respect to the lower pulley, right? According to your equation, aa+ab=0... But this is clearly not true because both a and b will moving with some nonzero acceleration in the same direction (they will move with the same acceleration that the lower pulley is moving with.)
 

Related Threads for: Double Atwood machine

  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
14
Views
7K
  • Last Post
Replies
2
Views
5K
  • Last Post
Replies
7
Views
6K
  • Last Post
Replies
1
Views
2K
Replies
12
Views
40K
  • Last Post
Replies
1
Views
4K
Top