**1. The problem statement, all variables and given/known data**

Lewis Hamilton is testing his new McLaren when suddenly he misses the pitlane break point and crashes into Kimi Raikkonen's Ferrari at 280 km/h. If Kimi was driving at 50km/h and the impact lasts for 0.3s and the coefficiant of friction is 0.3:

A) How far does each car slide?

B) Supposing that humans cannot survive over 80Gs, do either one of the drivers survive?

**2. Relevant equations**

impulse

p=p`

F=ma

**3. The attempt at a solution**

280km/h = 77.7 m/s

50kkm/h = 13.9 m/s

m1v1 + m2v2 = m1v1` + m2v2`

605(77.7) + 605(13.9) = 605(v1`) + 605(v2`)

V1` = 91.6 - V2`

v1 - v2 = v2` - v1`

77.7 - 13.9 = v2` - (91.6 - v2`)

V2` = 77.7 m/s

v1` = 13.9 m/s

//KIMI RAIKKONEN SLIDE

vf^2 - vi^2 = 2(a)(s)

a = -Ff / m

a = -ug

a = 0.3(9.8) = -2.94

0^2 - (77.7)^2 = 2(-2.94)(s)

s = 1026.75m

//LEWIS HAMILTON SLIDE

vf^2 - vi^2 = 2(a)(s)

a = -Ff / m

a = -ug

a = 0.3(9.8) = -2.94

0^2 - (13.9)^2 = 2(-2.94)(s)

s = 32.85m

//G FORCE FOR LEWIS HAMILTON

v1 = 605(77.7) = 47008.5

v1` = 605(13.9) = 8409.5

change in momentum = v1 - v1` = 38599

38599 = F * t

38599 = F * 0.3

F = 128663

G force = F / 9.8 = 13128.9

//G FORCE FOR KIMI RAIKKONEN

v1 = 605(13.9) = 8409.5

v1` = 605(77.7) = 47008.5

change in momentum = v1 - v1` = -38599

-38599 = F * t

-38599 = F * 0.3

F = -128663

G force = F / 9.8 = -13128.9

Okay! Now the thing is, those G forces looks REALLY high. I mean obviously the crash is going to produce a big number but I was guessing it would be between 75-200. Right now as you can see it's in the thousands.

Did I miss something?

P.S. I realize that this is obviously missing like a million real-world factors but it's for a high school physics class so no need to make it excessive with stuff we have not learned yet.

Thanks!!