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## Homework Statement

I have got double contour integral:

And here is picture:

I know every line equation as well.

The task is to calculate this integral as:

1. surface integral of outside of the area (in the picture)

2. using Ostrogradsky formula

## Homework Equations

Equation of plane: 4x+3y+12z-12=0

It means that x=3-0.75y-3z and z=1-0.25y-(1/3)x

## The Attempt at a Solution

I guess, this can be integral for task 1, when we use surface integral:

Can someone chek, if it's correct? And how to start task 2, when I have to use Ostrogradsky formula?