(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

How many stationary states exist for this potential? What are the allowed energies if the strength of the well, [tex]\alpha= \hbar^2/ma[/tex] and [tex]\hbar^2/4ma[/tex] where a= the position of the well(one at a, one at -a)

2. Relevant equations

[tex] V(x) = -\alpha(\delta(x+a) +\delta(x-a))[/tex]

[tex]E_{one delta well} = -m\alpha^2/2\hbar^2[/tex]

3. The attempt at a solution

OK, i may need to do more work for this but I want to see if I may not need to. First, the potential should have two bound states, one for each well, since one delta well can have one bound state.

Next, this is my question can I use the formula derived for the energy of the bound state of one delta well above and just assume the energies are the same for each state? Or do I have to go and solve for a new energy formula from the shrodinger EQ. If this is the case, please tell me and I'll work on it and put up my work for that. Thanks for your insight.

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# Double Delta Function Potential

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