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If all x,a,b and c are all natural numbers, is this true?

[itex] x^{a^b} = (x^{a^{b-1}})^a[/itex]

Proof

if [itex] c = a^{b-1}[/itex]

[itex] ca = (a^{b-1})a = a^b [/itex]

and [itex] (x^c)^a = x^{ca} = x^{a^b} [/itex]

Could I please have some feedback on this,

Thanks

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# Double Exponents Question

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