Evaluate the integral:
integral D of y sin (x+y^2) dA where
D = [0x2] x [0x2] U [1,3] x [1,3]
The Attempt at a Solution
So D is basically a square which simplifies to D = [1,2] x [1,2] since that is the portion of both rectangles that overlap.
So then my integral becomes
integral from 1 to 2 (integral from 1 to 2 of y sin (x+y^2) dy) dx
So the indefinite inner integral is:
So here I am supposed to evaluate y at 2 and 1 right? If that's correct, I am getting a wrong answer for some odd reason I think. I'm using wolfram alpha to check and their answer for the inner integral is:
Am i doing something wrong?
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