1. The problem statement, all variables and given/known data Evaluate the integral: integral D of y sin (x+y^2) dA where D = [0x2] x [0x2] U [1,3] x [1,3] 2. Relevant equations 3. The attempt at a solution So D is basically a square which simplifies to D = [1,2] x [1,2] since that is the portion of both rectangles that overlap. So then my integral becomes integral from 1 to 2 (integral from 1 to 2 of y sin (x+y^2) dy) dx So the indefinite inner integral is: -1/2(cos(x+y^2)) So here I am supposed to evaluate y at 2 and 1 right? If that's correct, I am getting a wrong answer for some odd reason I think. I'm using wolfram alpha to check and their answer for the inner integral is: http://www4d.wolframalpha.com/Calculate/MSP/MSP46819i63f8i8617ih80000063597a8d4817fhid?MSPStoreType=image/gif&s=41&w=259&h=36 [Broken] Am i doing something wrong?