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## Homework Statement

Evaluate the integral:

integral D of y sin (x+y^2) dA where

D = [0x2] x [0x2] U [1,3] x [1,3]

## Homework Equations

## The Attempt at a Solution

So D is basically a square which simplifies to D = [1,2] x [1,2] since that is the portion of both rectangles that overlap.

So then my integral becomes

integral from 1 to 2 (integral from 1 to 2 of y sin (x+y^2) dy) dx

So the indefinite inner integral is:

-1/2(cos(x+y^2))

So here I am supposed to evaluate y at 2 and 1 right? If that's correct, I am getting a wrong answer for some odd reason I think. I'm using wolfram alpha to check and their answer for the inner integral is:

http://www4d.wolframalpha.com/Calculate/MSP/MSP46819i63f8i8617ih80000063597a8d4817fhid?MSPStoreType=image/gif&s=41&w=259&h=36 [Broken]

Am i doing something wrong?

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