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y limits:

Upper: Sqrt(2 - x^2) from the equation 2 = y^2 + x^2

Lower: 0

X limits:

Upper: 2

Lower: -2

So I have to find the integral with respect to y of 2x-y with limits 0 to Sqrt[2-x^2]

After integrating with respect to Y I got:

2x(Sqrt[2-x^2]) - 1 + (x^2)/2

Is this correct to start with? Then integrate with respect to x from -2 to 2?