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## Homework Statement

Consider the volume of a solid bounded by the cone: z = sqrt(x^2 + y^2) and the top half of the sphere x^2 + y^2 + z^2 = 18 that is for z >= 0

Using cylindrical coordinates, express the volume as a double integral.

## Homework Equations

easy to sketch.. we can pretty easily figure r = 3 and theta = 2 pi

## The Attempt at a Solution

I got integral of sqrt(18 - r^2) r.dr.d(theta) over r = { (rcos(theta), rsin(theta) | 0 <= r <= 3, 0 <= theta <= 2pi

but answer says... [sqrt(18-r^2) - r ] r.dr.d(theta) where have i gone wrong

thanks in advance for the help!