Double Integral problem

  • Thread starter synergix
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  • #1
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Homework Statement



question 2:
http://www.math.ubc.ca/~haber/courses/math253/Welcome_files/asgn5.pdf" [Broken]

The Attempt at a Solution



So for part a) I tried to plot my domain of integration and ended up concluding it was an area bounded by y=0, y=4-x^2, and x=1. Is this okay?

In not too sure about part b) I'm just going off the graph here and so if thats wrong this will be wrong. Here is what i did I changed x domain from 1->(4-x^2) to 1->2 and I changed y domain from 0->3 to 0->4-x^2.

Is this correct?

Thanks!
 
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Answers and Replies

  • #2
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how could we integrate when the upper bound of the first integral is a polynomial x=4-x^2? Maybe I am misunderstanding something. Would it not have to be either a constant or a function of y?
 
  • #3
LCKurtz
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The upper limit on the inner integral is surely a typo and probably is supposed to be x = 4 - y2.
 
  • #4
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I sure hope so. Thank you.
 

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