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Double integral with polar

  1. Nov 12, 2007 #1
    1. Integrate f(x,y)=x+y
    1<=x^2+y^2<=4, x>=0, y>=0

    3. ∬x+y dxdy x=rcos(o) y=rsin(o)

    r is from 1 to 4, o is from 0 to pi/2

    I get the wrong answer and don't know why
  2. jcsd
  3. Nov 12, 2007 #2

    r doesn't go from 1 to 4. r^2 goes from 1 to 4.
    the 0 to pi/2 seems good.

    Don't know about the rest of the integral though sorry haven't learned polars yet :/
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