- #26

Mark44

Mentor

- 35,204

- 7,010

The line x = 1 (one boundary of the region of integration) can be converted to polar this way:

r*cos(theta) = 1 ==> r = 1/cos(theta) = sec(theta).

The circle's equation is x^2 + y^2 = 2x. Converting to polar, you get this:

r^2 = 2rcos(theta) ==> r = 2cos(theta), which I get by dividing both sides of the first equation by r.