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Double Integral

  1. Dec 18, 2004 #1


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    I am asked to calculate the double integral of the function

    [tex]f(x,y) = (2x+3y)^2 = 4x^2 + 12xy + 9y^2[/tex]

    on the domain defined by a triangle whose summits(?) are at (-1,0), (0,1) and (1,0). I chose to integrate from left to right. So the bounds of my integral are

    [tex]\int_0^1 \int_{y-1}^{1-y} (4x^2 + 12xy + 9y^2)dxdy[/tex]
  2. jcsd
  3. Dec 18, 2004 #2


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    Dearly Missed

    1) Vertices, not summits
    2) Looks good to me
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