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Double Integration

  1. Nov 11, 2007 #1
    1. ∬(4-y^2 )dxdy
    bounded region between y^2=2x and y^2=8-2x


    I took the integral 4-y^2 dx and got 4x-xy^2 from 0-4 = 16-4y^2
    then I took the integral 16-4y^2 dy from -2-2 = 128/3

    It is wrong and I don't know what to do.
     
  2. jcsd
  3. Nov 11, 2007 #2
    draw a picture of y^2=2x and y^2=8-2x on a graph and the limits of integration will become more clear

    but to do that first solve for y
     
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