could someone please check my work on the following problem:(adsbygoogle = window.adsbygoogle || []).push({});

Find the volume under [itex]z= 2x + y^2[/itex] and above the region bounded by [itex]x= y^2[/itex] and [itex]x= y^3[/itex].

endpoints of region: (0,0) and (1,1)

[tex] V = \int_{0}^{1}\int_{0}^{1} (2x + y^2) \,dx\,dy = \int_{0}^{1} [x^2 + xy^2]|_{0}^{1}\,dy = (x^2 y + \frac{1}{3}xy^2)|_{(0,0)}^{(1,1)} = \frac{4}{3} [/tex]

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# Homework Help: Double integration

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