(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A double loop circuit is shown in the figure below.

The Emf εx = 7.00 V and the Emf εw = 17.00 V. Both are shown on the diagram. Calculate the power dissipated in the 7 Ω resistor located on the extreme right in the circuit.

3. The attempt at a solution

I always get confused with the direction this goes. I start out with the joint rule.

I1= I2 + I3 + I4 + I5 + I6

say I1 = the amps going through the seven ohm resister

I2 = " " that going through bottom 2 ohm

I3 = " " middle 4 ohm

I4 = " " middle 5 ohm

I5 = " " upper 4 ohm

I6 = " " left 2 ohm

Then I do one loop, say the rightmost

-7*I1 - 2*I2 - 4*I3 + 7V - 5*I4 - 17V = 0

then the right most loop

5*I4 -7V + 4*I3 - 2*I6 - 4*I5 = 0

is this the right way or completely wrong? any help would GREATLY be appreciated.. soon hah

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# Double loop circuit problem.

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