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Introductory Physics Homework Help
Double slit - find wavelength
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[QUOTE="Ibix, post: 5606847, member: 365269"] ##x_m## is the distance off axis of the mth maximum, numbering the central bright spot as ##m=0##. You can immediately write the distance between the Mth and mth maxima as ##x_M-x_m=(M-m)L\lambda/d##. A little manipulation gets you ##\lambda=d (x_M-x_m)/L (M-m)##. You provided the distance between the M=5 and m=1 maxima. Plugging that and your other data in gets you ##\lambda=610##nm. You also gave the angle to the 8th maximum, which tells us that the distance from the axis to the 8th maximum is 3.02 sin(1.12)=0.059m. Plugging that in with M=8, m=0 also yields 610nm. [/QUOTE]
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Introductory Physics Homework Help
Double slit - find wavelength
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