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Double sum

  • Thread starter sapiental
  • Start date
118
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1. Homework Statement

Compute the following double sum

(n=3)(i=0)[tex]\sum[/tex](n=2)(j=0)[tex]\sum[/tex](3i+2j)



2. Homework Equations

sums

3. The Attempt at a Solution

my answer follows expanding the first sum, then just doing the last one

i get

(n=3)(i=0)[tex]\sum[tex](6+9i) = 78

thanks!
 

Answers and Replies

1,631
4
[tex]\sum_{i=0}^{n=3} \sum_{j=0}^{n=2}(3i+2j)=\sum_{i=0}^{n=3}(6+9i)=78[/tex]

Looks good to me.
 

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