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Double sum

  1. Apr 1, 2008 #1
    1. The problem statement, all variables and given/known data

    Compute the following double sum

    (n=3)(i=0)[tex]\sum[/tex](n=2)(j=0)[tex]\sum[/tex](3i+2j)



    2. Relevant equations

    sums

    3. The attempt at a solution

    my answer follows expanding the first sum, then just doing the last one

    i get

    (n=3)(i=0)[tex]\sum[tex](6+9i) = 78

    thanks!
     
  2. jcsd
  3. Apr 1, 2008 #2
    [tex]\sum_{i=0}^{n=3} \sum_{j=0}^{n=2}(3i+2j)=\sum_{i=0}^{n=3}(6+9i)=78[/tex]

    Looks good to me.
     
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