# Double sum

1. Homework Statement

Compute the following double sum

(n=3)(i=0)$$\sum$$(n=2)(j=0)$$\sum$$(3i+2j)

2. Homework Equations

sums

3. The Attempt at a Solution

my answer follows expanding the first sum, then just doing the last one

i get

(n=3)(i=0)$$\sum[tex](6+9i) = 78 thanks! ## Answers and Replies Related Calculus and Beyond Homework Help News on Phys.org [tex]\sum_{i=0}^{n=3} \sum_{j=0}^{n=2}(3i+2j)=\sum_{i=0}^{n=3}(6+9i)=78$$

Looks good to me.