1. The problem statement, all variables and given/known data You dive straight down into a pool of water. You hit the water with a speed of 7.0m/s, and your mass is 75kg. Assuming a drag force of the form F_D = (−1.00×10^4kg/s)*v, how long does it take you to reach 2% of your original speed? (Ignore any effects of buoyancy.) 2. Relevant equations F_D = (-1.00*10^4kg/s)*v F_g = m*g F_net = F_D - F_g (V_f - V_i) / a = t 3. The attempt at a solution I have tried various attempts at this solution, all of them giving the wrong answer, and I have one chance left at the question before it gives me 0%. I assumed the general approach would be as follows: V_i = 7m/s V_f = 0.14m/s m = 75kg F_g = 735N F_D = (-10000*v) - this part is confusing me, as I'm unsure which velocity value to use, but I have come up with 68600N using the change in initial velocity and final velocity. F_D = (-10000kg/s * (0.14m/s - 7m/s) = 68600N Given that F_Net = 68600N - 735N, m*a = 67865N a=904.8667m/s^2 (this value seems incredibly large, suggesting I have done something wrong at this point) Anyways, plugging into my kinematics equation supplied, I get: (0.14m/s - 7m/s)/-904.8667m/s^2 = 0.00758s. This answer, obviously, is quite wrong. Which value of velocity should I be using in the F_D formula?