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Drag Force

  1. Jul 11, 2009 #1
    1. The problem statement, all variables and given/known data
    A baseball is thrown straight up. The drag force is proportional to v^{2}.
    In terms of g, what is the y-component of the ball's acceleration when its speed is half its terminal speed and it is moving up? In terms of g, what is the y-component of the ball's acceleration when its speed is half its terminal speed and it is moving back down?

    2. Relevant equations

    v terminal = [tex]\sqrt{mg/D}[/tex]

    3. The attempt at a solution
    I honestly have no idea how to attempt this problem
     
  2. jcsd
  3. Jul 11, 2009 #2
    The drag force is of the form:
    [tex]F_d = -kv^2[/tex]

    Or to use your notation:
    [tex]F_d = -Dv^2[/tex]

    The terminal velocity is achieved when the ball starts falling at a constant velocity. At that point, the following holds true:
    [tex]kv^2=mg[/tex]
     
  4. Jul 11, 2009 #3

    tiny-tim

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    Hi clarineterr! :wink:

    Start "acceleration = dv/dt = … " :smile:
     
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