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Drag, position of a ball

  • Thread starter hello337
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  • #1
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Homework Statement


I have to make a plot. This plot must illustrates a position of a ball, which is falling. My problem is that I dont know what v is in this equation.
drag force= -C * ||v(t)|| * v

Homework Equations



To calculate the velocity:
v(t+dt)=v(t)+a(t)*dt
where t is time and dt is Δt

The position:
x(t+dt)=x(t)+v(t)*dt

To find a(t) (the acceleration) I use:
a(t)=F(t)/M

where M is the mass f the ball and F(t):

F(t)=force from gravity + drag force

And drag force is:
drag force= -C * ||v(t)|| * v


The Attempt at a Solution



I have discussed it with some from my class and some say v is v(t-dt) .. other say it is just v(t).
 

Answers and Replies

  • #2
gneill
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20,781
2,759

Homework Statement


I have to make a plot. This plot must illustrates a position of a ball, which is falling. My problem is that I dont know what v is in this equation.
drag force= -C * ||v(t)|| * v
Welcome to Physics Forums.

That looks like it might be a unit vector in the direction of the velocity. I notice that there's a "-" in front of the constant C. That would make the drag force operate in the opposite direction to the velocity, which is expected.
 
  • #3
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Thank you! So you think that v is v(t) ? :)
 
  • #4
gneill
Mentor
20,781
2,759
More likely v = v(t)/|v(t)| , making it a unit vector (magnitude of unity).
 

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