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A 14.0 kg block is dragged over a rough, horizontal surface by a 86.0 N force acting at 20.0° above the horizontal. The block is displaced 5.00 m, and the coefficient of kinetic friction is 0.300.

(a) Find the work done on the block by the 86.0 N force.

W=Fd so work=(86.0 N) ( 5m) =

430

(b) Find the work done on the block by the normal force.

Again this will be the force * distance. The force here is the normal force which is given by mgsin(20) then multiplied by the distance of 5?

(c) Find the work done on the block by the gravitational force.

Is this just the weight times the distance traveled...so sin(20)*mg*5

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# Homework Help: Dragged Block

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