I have a curve [itex]-\sqrt {2x^3 }[/itex] on which I'm supposed to draw a tangent that is perpendicular to the line [itex]\[y = \frac{4}{3}x + \frac{1}{3}[/itex].(adsbygoogle = window.adsbygoogle || []).push({});

I know that this tangent must have a "steepness" of -3/4 in order to make it perpendicular, but how do I now find the point on the graph?

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# Homework Help: Draw a tangent that is perpendicular to the line

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